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Here are some exam-style questions on this statement:
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The angle between a line and a plane is:
$$ \sin^{-1} \frac{|\mathbf{n \cdot d|}}{|\mathbf{n}| |\mathbf{d}|} $$\(\mathbf{d}\) is the direction vector of the line;
\(\mathbf{n}\) is the normal vector to the plane.
The angle between two planes can be found by finding the angles between their normals:
$$ \cos^{-1} \frac{|\mathbf{n_1 \cdot n_2|}}{|\mathbf{n_1}| |\mathbf{n_2}|} $$\(\mathbf{n_1}\) is the normal vector to the first plane;
\(\mathbf{n_2}\) is the normal vector to the second plane.
To find where two planes intersect.
For example:
$$x-3y+2z=8$$ $$3x-9y+2z=4$$Begin by writing the augmented matrix for the system of equations:
$$\left[\begin{array}{ccc|c}1 & -3 & 2 & 8\\3 & -9 & 2 & 4 \end{array} \right]$$We now perform row operations to transform this matrix into echelon form:
\(R2 = R2 - 3 \times R1\)
$$\left[\begin{array}{ccc|c}1 & -3 & 2 & 8\\0 & 0 & -4 & -20 \end{array}\right]$$Two planes in space could be intersecting, parallel or coincident.
from \(R2\) it can be seen that \( z=5 \)
from \(R1\) it can be seen that \(x\) and \(y\) can have infinitely many values so let \( y=t \)
from \(R1\) it can be seen that \( x=3t-2 \)
The planes intersect along the line defined by a vector equation, \( \mathbf{r} \). Let \(t = 0\) to find a point on the line: \( (-2,0,0) \)
$$ \mathbf{r} = \begin{pmatrix} -2 \\ 0 \\ 0 \end{pmatrix} \quad + \quad t \begin{pmatrix} 3 \\ 1 \\ 0 \end{pmatrix} $$To find where three planes intersect solve their equations simultaneously.
For example:
$$x+y+z=3$$ $$2x-y+z=0$$ $$x-2y-z=-3$$We begin by writing the augmented matrix for the system of equations:
$$\left[\begin{array}{ccc|c}1 & 1 & 1 & 3\\2 & -1 & 1 & 0\\1 & -2 & -1 & -3\end{array}\right]$$We now perform row operations to transform this matrix into echelon form:
\(R2 = R2 - 2 \times R1\)
$$\left[\begin{array}{ccc|c}1 & 1 & 1 & 3\\0 & -3 & -1 & -6\\1 & -2 & -1 & -3\end{array}\right]$$\(R3 = R3 - R1\)
$$\left[\begin{array}{ccc|c}1 & 1 & 1 & 3\\0 & -3 & -1 & -6\\0 & -3 & -2 & -6\end{array}\right]$$\(R3 = R3 - R2\)
$$\left[\begin{array}{ccc|c}1 & 1 & 1 & 3\\0 & -3 & -1 & -6\\0 & 0 & -1 & 0\end{array}\right]$$The augmented matrix is now in the form:
$$\left[\begin{array}{ccc|c}a & b & c & d\\0 & e & f & g\\0 & 0 & h & i\end{array}\right]$$If \( h \neq 0\) there is a unique solution.
If \( h = 0 \text{ and } i \neq 0 \) there is no solution
If \( h = 0 \text{ and } i = 0 \) there are infinitely many solutions (let \(z=t\)).
In the example above ...
from \(R3\) it can be seen that \( z=0 \)
from \(R2\) it can be seen that \( y=2 \)
from \(R1\) it can be seen that \( x=1 \)
The planes intersect at \( (1,2,0) \).
Intersections of a line with a plane: Substitute parametric expressions into plane equation then solve to find the paramater.
Intersections of two planes: Solve simultaneous equations by introducing a parameter or find vector product of normals if a common point is known.
Intersections of three planes: Solve simultaneous equations using augmented matrix row reduction.
Angle between a line and a plane: 90° - angle between direction of line and normal to the plane.
Angle between two planes: Find angle between the normals of the plane.
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