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International Baccalaureate Mathematics

Geometry and Trigonometry

Syllabus Content

Solving trigonometric equations in a finite interval, both graphically and analytically. Equations leading to quadratic equations in sinx, cosx or tanx

Here are some specific activities, investigations or visual aids we have picked out. Click anywhere in the grey area to access the resource.

Here are some exam-style questions on this statement:

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Here are some Advanced Starters on this statement:

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Furthermore

Official Guidance, clarification and syllabus links:

2sinx=1,0x2π

Examples:
2sin2x=3cosx,0x180
2tan(3(x4))=1,πx3π

2sin2x+5cosx+1=0 for 0x4π,
2sinx=cos2x,πxπ

Not required: The general solution of trigonometric equations.

Solving trigonometric equations within a finite interval involves finding all the angles that satisfy the equation within a given range. This can be approached graphically, by plotting the functions and identifying the points of intersection, or analytically, by manipulating the equation using trigonometric identities and inverse functions. When trigonometric equations reduce to a quadratic form in sinx, cosx, or tanx, we can solve them using algebraic techniques similar to those used for quadratic equations.

Key Formulae:
sin2x+cos2x=1
1+tan2x=sec2x
sin(2x)=2sinxcosx
cos(2x)=cos2xsin2x=2cos2x1=12sin2x

Example:
To solve the equation 2sin2xsinx1=0 for 0x2π:
Let u=sinx. The equation becomes 2u2u1=0.
Solving this quadratic equation, we find u=12 or u=1.
Returning to x, we have sinx=12 or sinx=1.
This yields the solutions x=7π6,11π6 or x=π2 within the given interval.

This video on Solving Trig Functions and Equations is from Revision Village and is aimed at students taking the IB Maths AA SL/HL course.

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